125=(1/25)^y-1

Solution for 125=(1/25)^y-1 equation:

125=(1/25)^y-1

We move all terms to the left:

125-((1/25)^y-1)=0


Domain of the equation: 25)^y-1)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-((+1/25)^y-1)+125=0

We multiply all the terms by the denominator


-((+1+125*25)^y-1)=0


We calculate terms in parentheses: -((+1+125*25)^y-1), so:

(+1+125*25)^y-1

We add all the numbers together, and all the variables

3126^y-1

Back to the equation:

-(3126^y-1)


We get rid of parentheses

-3126^y+1=0

We move all terms containing y to the left, all other terms to the right

-3126^y=-1

y=-1/1

y=-1